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Update 0454.四数相加II，力扣函数参数更新，故更新对应题解代码 #2907

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Update 0454.四数相加II，力扣函数参数更新，故更新对应题解代码 #2907

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10 changes: 5 additions & 5 deletions problems/0454.四数相加II.md
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Original file line number Diff line number Diff line change
Expand Up @@ -62,18 +62,18 @@ C++代码:
```CPP
class Solution {
public:
int fourSumCount(vector<int>& A, vector<int>& B, vector<int>& C, vector<int>& D) {
int fourSumCount(vector<int>& nums1, vector<int>& nums2, vector<int>& nums3, vector<int>& nums4) {
unordered_map<int, int> umap; //key:a+b的数值，value:a+b数值出现的次数
// 遍历大A和大B数组，统计两个数组元素之和，和出现的次数，放到map中
for (int a : A) {
for (int b : B) {
for (int a : nums1) {
for (int b : nums2) {
umap[a + b]++;
}
}
int count = 0; // 统计a+b+c+d = 0 出现的次数
// 再遍历大C和大D数组，找到如果 0-(c+d) 在map中出现过的话，就把map中key对应的value也就是出现次数统计出来。
for (int c : C) {
for (int d : D) {
for (int c : nums3) {
for (int d : nums4) {
if (umap.find(0 - (c + d)) != umap.end()) {
count += umap[0 - (c + d)];
}
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