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Copy path11. Container With Most Water.cpp
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11. Container With Most Water.cpp
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You are given an integer array height of length n.
There are n vertical lines drawn such that the two endpoints of the ith line are (i, 0) and (i, height[i]).
Find two lines that together with the x-axis form a container, such that the container contains the most water.
Return the maximum amount of water a container can store.
Notice that you may not slant the container.
Example 1:
Input: height = [1,8,6,2,5,4,8,3,7]
Output: 49
Explanation: The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7].
In this case, the max area of water (blue section) the container can contain is 49.
Example 2:
Input: height = [1,1]
Output: 1
Constraints:
n == height.length
2 <= n <= 105
0 <= height[i] <= 104
class Solution {
public:
int maxArea(vector<int>& height) {
int res = 0, start = 0, end = height.size() - 1;
while (start <= end) {
int water = min(height[start], height[end]) * (end - start);
res = max(res, water);
if (height[start] <= height[end]) start++;
else end--;
}
return res;
}
};