Convert Numbers to Roman Numerals

1. Take a decimal number as input.
2. Check if the number is greater than 1000 or 900 or 500 or 400 or 100 or 90 or 50 or 40 or 10 or 9 or 5 or 4 or 1.
3. If it is, then store its equivalent roman number in a array.
4. Repeat the step 2-3 with the left over number.

Author: rohank04

Convert Numbers to Roman Numerals

@@ -0,0 +1,123 @@
+#include <stdio.h>
+ 
+void predigit(char num1, char num2);
+void postdigit(char c, int n);
+ 
+char romanval[1000];
+int i = 0;
+int main()
+{
+    int j;
+    long number;
+ 
+    printf("Enter the number: ");
+    scanf("%d", &number);
+    if (number <= 0)
+    {
+        printf("Invalid number");
+        return 0;
+    }
+    while (number != 0)
+    {
+        if (number >= 1000)
+        {
+            postdigit('M', number / 1000);
+            number = number - (number / 1000) * 1000;
+        }
+        else if (number >= 500)
+        {
+            if (number < (500 + 4 * 100))
+            {
+                postdigit('D', number / 500);
+                number = number - (number / 500) * 500;
+            }
+            else
+            {
+                predigit('C','M');
+                number = number - (1000-100);
+            }
+        }
+        else if (number >= 100)
+        {
+            if (number < (100 + 3 * 100)) 
+            {
+                postdigit('C', number / 100);
+                number = number - (number / 100) * 100;
+            }
+            else
+            {
+                predigit('L', 'D');
+                number = number - (500 - 100);
+            }
+        }
+        else if (number >= 50 )
+        {
+            if (number < (50 + 4 * 10))
+            {
+                postdigit('L', number / 50);
+                number = number - (number / 50) * 50;
+            }
+            else
+            {
+                predigit('X','C');
+                number = number - (100-10);
+            }
+        }
+        else if (number >= 10)
+        {
+            if (number < (10 + 3 * 10))
+            {
+                postdigit('X', number / 10);
+                number = number - (number / 10) * 10;
+            }
+            else
+            {
+                predigit('X','L');
+                number = number - (50 - 10);
+            }
+        }
+        else if (number >= 5)
+        {
+            if (number < (5 + 4 * 1))
+            {
+                postdigit('V', number / 5);
+                number = number - (number / 5) * 5;
+            }
+            else
+            {
+                predigit('I', 'X');
+                number = number - (10 - 1);
+            }
+        }
+        else if (number >= 1)
+        {
+            if (number < 4)
+            {
+                postdigit('I', number / 1);
+                number = number - (number / 1) * 1;
+            }
+            else
+            {
+                predigit('I', 'V');
+                number = number - (5 - 1);
+            }
+        }
+    }
+    printf("Roman number is: ");
+    for(j = 0; j < i; j++)
+        printf("%c", romanval[j]);
+    return 0;
+}
+ 
+void predigit(char num1, char num2)
+{
+    romanval[i++] = num1;
+    romanval[i++] = num2;
+}
+ 
+void postdigit(char c, int n)
+{
+    int j;
+    for (j = 0; j < n; j++)
+        romanval[i++] = c;
+}