Skip a test (or silently drop) if there are no parameters for it

[ToveRumar]

I am using

pytest_generate_tests(metafunc):

to generate my test parameters from a config file, So far so good!

However, if I can not find any matching configurations in this configfile to pass as params, there seems to be no clean way of skipping or dropping that test.

I have tried using

pytest.skip()

but then the whole module of tests seem to be skipped which I do not want.

This is pseudocode for what my conftest.py is doing:

def pytest_generate_tests(metafunc):
    test_requirements = get_test_requirements()
    configurations= get_configurations(requirements)
    if configurations:
        metafunc.parametrize('fixture', configurations, indirect=True , ids=lambda d: d.name)
    else:
        SKIP THIS TEST

My solution so far is

 metafunc.parametrize('fixture', [pytest.param(None, marks=pytest.mark.skip(reason="No config for test"))]) 

However i would like something more elegant if possible.

I think its useful to be able to generate tests at collection time to see what tests should/would be run with the current configuration setup you have.

Do you know any way to do this?

[webknjaz]

You can deselect those tests, then they won't show up as skipped: https://github.com/aio-libs/multidict/blob/bc86d23/tests/conftest.py#L189-L210.

[ToveRumar]

Thanks! Ill try this solution, looks like it can be exactly what i need!

[RonnyPfannschmidt]

Instead of using a empty parameters set, use a dummy parameter that adds a per parameterization mark to skip that test

[ToveRumar]

Thank you for your suggestion! This is almost what my current solution is, however having a specific dummy parameter instead of None is definitely cleaner!