|
| 1 | +/* |
| 2 | + Given an array of integers nums, sort the array in ascending order and return it. |
| 3 | + Ex. nums = [5,2,3,1] -> [1,2,3,5] |
| 4 | +
|
| 5 | + Use Merge sort to sort the array. |
| 6 | +
|
| 7 | + Time - O(nlogn) |
| 8 | + Space - O(n) |
| 9 | +*/ |
| 10 | + |
| 11 | +class Solution { |
| 12 | + private: |
| 13 | + void merge(vector<int> &nums, int low, int mid, int high) { |
| 14 | + if(low >= high) |
| 15 | + return; |
| 16 | + |
| 17 | + int l = low, r = mid + 1, k = 0, size = high - low + 1; |
| 18 | + vector<int> sorted(size, 0); |
| 19 | + |
| 20 | + while (l <= mid and r <= high){ |
| 21 | + if(nums[l] < nums[r]) |
| 22 | + sorted[k++] = nums[l++]; |
| 23 | + else |
| 24 | + sorted[k++] = nums[r++]; |
| 25 | + } |
| 26 | + |
| 27 | + while(l <= mid) |
| 28 | + sorted[k++] = nums[l++]; |
| 29 | + while(r <= high) |
| 30 | + sorted[k++] = nums[r++]; |
| 31 | + |
| 32 | + for(k = 0; k < size; k++) |
| 33 | + nums[k + low] = sorted[k]; |
| 34 | + } |
| 35 | + |
| 36 | + void mergeSort(vector<int>& nums, int low, int high){ |
| 37 | + if(low >= high) |
| 38 | + return; |
| 39 | + |
| 40 | + int mid = low + (high - low) / 2; |
| 41 | + |
| 42 | + mergeSort(nums, low, mid); |
| 43 | + mergeSort(nums, mid + 1, high); |
| 44 | + merge(nums, low, mid, high); |
| 45 | + } |
| 46 | + |
| 47 | +public: |
| 48 | + vector<int> sortArray(vector<int>& nums) { |
| 49 | + mergeSort(nums, 0, nums.size()-1); |
| 50 | + return nums; |
| 51 | + } |
| 52 | +}; |
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