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+ class Solution {
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+ private static int treeDiameter = 0 ;
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+
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+ public int diameterOfBinaryTree (TreeNode root ) {
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+ calculateHeight (root );
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+ return treeDiameter -1 ;
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+ }
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+
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+ private static int calculateHeight (TreeNode currentNode ) {
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+ if (currentNode == null )
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+ return 0 ;
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+
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+ int leftTreeHeight = calculateHeight (currentNode .left );
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+ int rightTreeHeight = calculateHeight (currentNode .right );
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+
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+ // if the current node doesn't have a left or right subtree, we can't have
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+ // a path passing through it, since we need a leaf node on each side
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+ if (leftTreeHeight != 0 && rightTreeHeight != 0 ) {
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+
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+ // diameter at the current node will be equal to the height of left subtree +
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+ // the height of right sub-trees + '1' for the current node
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+ int diameter = leftTreeHeight + rightTreeHeight + 1 ;
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+
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+ // update the global tree diameter
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+ treeDiameter = Math .max (treeDiameter , diameter );
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+ }
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+
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+ // height of the current node will be equal to the maximum of the heights of
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+ // left or right subtrees plus '1' for the current node
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+ return Math .max (leftTreeHeight , rightTreeHeight ) + 1 ;
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+ }
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+ }
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