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JumpGame.java
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package com.leetcode;
import java.util.HashMap;
public class JumpGame {
//https://leetcode.com/problems/jump-game/
/**
Input: nums = [2,3,1,1,4]
Output: true
Explanation: Jump 1 step from index 0 to 1, then 3 steps to the last index.
**/
class Solution {
public boolean canJump(int[] nums) {
int reach=0,n=nums.length;
for(int i=0;i<n;i++)
{
reach=Math.max(reach,i+nums[i]);
if(reach>=n-1)
return true;
if(!(reach>i))////means cannot go ahead than current reach < i or reach == i
return false;
}
return true;
}
}
// Recursion with Memo
class SolutionTLE {
boolean canReach;//just need one path
public boolean canJump(int[] nums) {
HashMap<Integer,Boolean> memo = new HashMap<>(); // to store if at index if can be reached.
int n = nums.length;
return backtrack(0,n-1,nums,memo);
}
public boolean backtrack(int start, int target , int [] nums, HashMap<Integer,Boolean> memo){
if(memo.containsKey(start)) return memo.get(start);
if(canReach) return false;//terminate if any one solution is found
if(start == target){
memo.put(start,true);
canReach = true;
return true;
}
int jump = nums[start];
boolean found = false;
for(int i = 1 ; i <=jump ; i++){
if(start+i <= target)
found = found || backtrack(start+i,target,nums,memo);
}
memo.put(start,found);
return found;
}
}
/**
* Simple Recursion solution to add memo later.
*/
class SolutionSimpleRec {
boolean canReach;//just need one path
public boolean canJump(int[] nums) {
canReach = false;
int n = nums.length;
backtrack(0,n-1,nums);
return canReach;
}
public void backtrack(int start, int target , int [] nums){
if(canReach) return;//terminate if any one solution is found
if(start == target){
canReach = true;
return;
}
int jump = nums[start];
for(int i = 1 ; i <=jump ; i++){
if(start+i <= target)
backtrack(start+i,target,nums);
}
}
}
}