When interacting with TimerOutputs.jl, only displays lowered code

[johnomotani]

If I try to debug a function that I'm also timing using TimerOutputs, only lowered code is displayed, and I cannot step normally through the function.

MWE:

julia> using TimerOutputs

julia> using Debugger

julia> my_timer = TimerOutput()
────────────────────────────────────────────────────────────────────
                           Time                    Allocations      
                  ───────────────────────   ────────────────────────
Tot / % measured:     91.5ms /   0.0%           4.68MiB /   0.0%    

Section   ncalls     time    %tot     avg     alloc    %tot      avg
────────────────────────────────────────────────────────────────────
────────────────────────────────────────────────────────────────────

julia> @timeit my_timer foo() = begin
       println("hello")
       end
foo (generic function with 1 method)

julia> @enter foo()
In foo() at none:0
  3  │          Core.NewvarNode(:(b₀#233))
  4  │          Core.NewvarNode(:(accumulated_data#232))
  5  │          local_to#230 = Main.my_timer
  6  │    %6  = local_to#230
> 7  │          enabled#231 = Base.getproperty(%6, :enabled)
  8  │    %8  = enabled#231
  9  └───       goto #3 if not %8
 10  2 ── %10 = local_to#230
 11  └───       accumulated_data#232 = (push!)(%10, "foo")

About to run: <getproperty(─────────────────────────────...>
1|debug> n
hello
In foo() at none:0
 28  10 ┄ %28 = @_8 === 1
 29  └───       goto #12 if not %28
 30  11 ─       Base.rethrow()
 31  12 ┄ %31 = val#235
>32  └───       return %31

About to run: return
1|debug> 

julia> 

This using Julia-1.11.3, Debugger-0.7.10 and TimerOutputs-0.5.27.

Obvious workaround is to take out the timing while I'm debugging, but that's not ideal especially in a bigger code where there might be many timed functions.

[KristofferC]

I think KristofferC/TimerOutputs.jl#164 made this slightly worse.