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63 lines (47 loc) · 1.26 KB

English Version

题目描述

选出所有 bonus < 1000 的员工的 name 及其 bonus。

Employee 表单

+-------+--------+-----------+--------+
| empId |  name  | supervisor| salary |
+-------+--------+-----------+--------+
|   1   | John   |  3        | 1000   |
|   2   | Dan    |  3        | 2000   |
|   3   | Brad   |  null     | 4000   |
|   4   | Thomas |  3        | 4000   |
+-------+--------+-----------+--------+
empId 是这张表单的主关键字

Bonus 表单

+-------+-------+
| empId | bonus |
+-------+-------+
| 2     | 500   |
| 4     | 2000  |
+-------+-------+
empId 是这张表单的主关键字

输出示例:

+-------+-------+
| name  | bonus |
+-------+-------+
| John  | null  |
| Dan   | 500   |
| Brad  | null  |
+-------+-------+

解法

SQL

# Write your MySQL query statement below
SELECT name, bonus
FROM
    Employee
    LEFT JOIN Bonus USING (empId)
WHERE ifnull(bonus, 0) < 1000;